Classify the following compounds in the form of alkyl, allylic, vinyl or benzylic halides: i) CH₃-CH=CH-Cl ii)

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Q. Classify the following compounds in the form of alkyl, allylic, vinyl or benzylic halides: i) CH₃-CH=CH-Cl ii) C₆H₅CH₂I iii) CH₃-CH(Br)-CH₃ iv) CH₂=CH-Cl

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Step 1. i) CH3-CH=CH-Cl: the chlorine sits directly on an sp2 carbon that is itself part of the C=C double bond -- the defining feature of a vinylic halide.

Step 2. ii) C6H5CH2I: the iodine sits on the carbon directly attached to (but not part of) the aromatic ring -- a benzylic halide.

Step 3. iii) CH3-CH(Br)-CH3: this is 2-bromopropane, an ordinary saturated sp3 carbon bearing Br, two CH3 groups and H -- a plain (secondary) alkyl halide, with no double bond or ring nearby.

Step 4. iv) CH2=CH-Cl: vinyl chloride itself -- Cl again sits directly on an sp2, double-bond carbon, so it is vinylic, exactly like (i).

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i) CH3-CH=CH-Cl is vinylic; ii) C6H5CH2I is benzylic; iii) CH3-CH(Br)-CH3 is a secondary alkyl halide; iv) CH2=CH-Cl is vinylic.

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Q.Classify the following compounds in the form of alkyl, allylic, vinyl or benzylic halides: i) CH₃-CH=CH-Cl ii) C₆H₅CH₂I iii) CH₃-CH(Br)-CH₃ iv) CH₂=CH-Cl

Concept understanding — Classification of Organic Halogen Compounds

Q.Classify the following compounds in the form of alkyl, allylic, vinyl or benzylic halides: i) CH₃-CH=CH-Cl ii) C₆H₅CH₂I iii) CH₃-CH(Br)-CH₃ iv) CH₂=CH-Cl

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