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Choose the Best Answer · Q26

Q.An alkane is obtained by decarboxylation of sodium propionate. Same alkane can be prepared by

(a) Catalytic hydrogenation of propene
(b) action of sodium metal on iodomethane
(c) reduction of 1-chloro propane
(d) reduction of bromomethane
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Step 1. Sodium propionate is the sodium salt of propionic (propanoic) acid, CH3CH2COONa (three carbons); decarboxylating it with soda lime removes the -COONa group as Na2CO3, leaving an alkane with ONE FEWER carbon than the acid -- i.e. ethane (C2H6, two carbons).

Step 2. The question asks which OTHER method also gives this same alkane, ethane. Catalytic hydrogenation of propene (option a) gives PROPANE (three carbons) -- the wrong carbon count, ruled out.

Step 3. Action of sodium metal on iodomethane (option b) is a Wurtz reaction on a ONE-carbon halide: 2 CH3I + 2Na --dry ether--> CH3-CH3 (ethane) + 2NaI -- exactly two carbons, matching the target. …

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