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Choose the Best Answer · Q30

Q.2-butyne on chlorination gives

(a) 1-chloro butane
(b) 1,2-dichloro butane
(c) 1,1,2,2-tetrachlorobutane
(d) 2,2,3,3-tetra chloro butane
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Step 1. 2-Butyne, CH3-C≡\equivC-CH3, is a symmetric INTERNAL alkyne with the triple bond between C2 and C3.

Step 2. Chlorination of an alkyne proceeds stepwise, exactly like bromination: the first mole of Cl2 adds across the triple bond to give a 2,3-dichlorobut-2-ene (a vicinal dichloroalkene, CH3-CCl=CCl-CH3), and with excess Cl2 a second mole adds across that remaining double bond.

Step 3. Since both chlorines of the first addition sit on C2 and C3, and the second addition places one MORE chlorine on each of those same two carbons, the final product carries TWO chlorines on C2 and TWO chlorines on C3 -- CH3-CCl2-CCl2-CH3. …

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