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Write Brief Answer · Q33

Q.State and explain Henry's law

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✓ Free question

Step 1. Statement. Henry's law states that, at low concentrations, the partial pressure of a gas in the vapour phase above a solution (its vapour pressure) is directly proportional to the mole fraction of that gaseous solute dissolved in the solution.

Step 2. Mathematical form. psolute∝xsolute in solutionp_{solute}\propto x_{solute\ in\ solution}, i.e. psolute=KH xsolute in solutionp_{solute}=K_H\,x_{solute\ in\ solution}, where KHK_H (Henry's law constant) is an empirical constant with the dimensions of pressure, whose value depends on the identity of both the gas and the solvent.

Step 3. Explanation. A plot of psolutep_{solute} against xsolutex_{solute} is a straight line through the origin, of slope KHK_H. A gas with a LARGER KHK_H is LESS soluble (a given mole fraction produces a larger pressure); a gas with a SMALLER KHK_H is MORE soluble. The law breaks down at high pressure/temperature, for gases that chemically react with the solvent (e.g. NH3_3 or HCl with water), and for gases that associate or dissociate while dissolving.

✓Final answer

Henry's law: psolute=KH xsolute in solutionp_{solute}=K_H\,x_{solute\ in\ solution} -- the partial pressure of a gas above a dilute solution is directly proportional to its mole fraction dissolved in that solution.

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