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Exercise 2.9 · Q11

Q.2x2+5x−11x2+2x−3\dfrac{2x^2+5x-11}{x^2+2x-3}

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Step 1. Divide: 2x2+5x−11=2(x2+2x−3)+(x−5)2x^2+5x-11=2(x^2+2x-3)+(x-5) (check: 2(x2+2x−3)=2x2+4x−62(x^2+2x-3)=2x^2+4x-6, and (2x2+5x−11)−(2x2+4x−6)=x−5(2x^2+5x-11)-(2x^2+4x-6)=x-5).

Step 2. So 2x2+5x−11x2+2x−3=2+x−5(x+3)(x−1)\dfrac{2x^2+5x-11}{x^2+2x-3}=2+\dfrac{x-5}{(x+3)(x-1)}. …

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