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Exercise 2.9 · Q9

Q.x+12(x+1)2(x−2)\dfrac{x+12}{(x+1)^2(x-2)}

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Step 1. Write x+12(x+1)2(x−2)=Ax+1+B(x+1)2+Cx−2\dfrac{x+12}{(x+1)^2(x-2)}=\dfrac A{x+1}+\dfrac B{(x+1)^2}+\dfrac C{x-2}, so x+12=A(x+1)(x−2)+B(x−2)+C(x+1)2x+12=A(x+1)(x-2)+B(x-2)+C(x+1)^2.

Step 2. x=−1x=-1: 11=B(−3)⇒B=−11311=B(-3)\Rightarrow B=-\dfrac{11}3. x=2x=2: 14=C(9)⇒C=14914=C(9)\Rightarrow C=\dfrac{14}9. …

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