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Question 110 of 128

Q.Resolve into partial fractions: x(x+3)(x−4)\dfrac{x}{(x+3)(x-4)}.

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2022Subjective· 3mImportance★★★★★
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Partial fractions give x(x+3)(x−4)=3/7x+3+4/7x−4\dfrac{x}{(x+3)(x-4)} = \dfrac{3/7}{x+3}+\dfrac{4/7}{x-4}.

Let x(x+3)(x−4)=Ax+3+Bx−4\dfrac{x}{(x+3)(x-4)} = \dfrac{A}{x+3}+\dfrac{B}{x-4}.

Multiplying both sides by (x+3)(x−4)(x+3)(x-4): x=A(x−4)+B(x+3)x = A(x-4)+B(x+3).

Set x=−3x=-3: −3=A(−7)⇒A=37-3 = A(-7) \Rightarrow A = \dfrac{3}{7}.

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