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Exercise 4.4 · Q9

Q.Prove by Mathematical Induction that
[!FORMULA] 1!+(2×2!)+(3×3!)+⋯+(n×n!)=(n+1)!−1.1!+(2\times 2!)+(3\times 3!)+\cdots+(n\times n!) = (n+1)!-1.

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Let P(n):1!+2×2!+3×3!+⋯+n×n!=(n+1)!−1P(n):1!+2\times2!+3\times3!+\cdots+n\times n!=(n+1)!-1.

Step 1. Base case. P(1)P(1): LHS =1!=1=1!=1; RHS =2!−1=1=2!-1=1. True.

Step 2. Inductive hypothesis. Assume P(k):1!+2×2!+⋯+k×k!=(k+1)!−1P(k):1!+2\times2!+\cdots+k\times k!=(k+1)!-1. …

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