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Exercise 10.3 · Q13

Q.Differentiate the following: y=(2x−5)4(8x2−5)−3y = (2x-5)^4(8x^2-5)^{-3}

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Step 1. Write y=uvy=uv with u=(2x−5)4u=(2x-5)^4 and v=(8x2−5)−3v=(8x^2-5)^{-3}.

Step 2. Differentiate uu using the chain rule: u′=4(2x−5)3⋅2=8(2x−5)3u'=4(2x-5)^3\cdot 2=8(2x-5)^3.

Step 3. Differentiate vv using the chain rule: v′=−3(8x2−5)−4⋅16x=−48x(8x2−5)−4v'=-3(8x^2-5)^{-4}\cdot 16x=-48x(8x^2-5)^{-4}.

Step 4. Apply the product rule: y′=u′v+uv′=8(2x−5)3(8x2−5)−3−48x(2x−5)4(8x2−5)−4y'=u'v+uv' = 8(2x-5)^3(8x^2-5)^{-3} - 48x(2x-5)^4(8x^2-5)^{-4}.

Step 5. Factor out the common terms (2x−5)3(8x2−5)−4(2x-5)^3(8x^2-5)^{-4}: y′=(2x−5)3(8x2−5)−4[8(8x2−5)−48x(2x−5)]y'=(2x-5)^3(8x^2-5)^{-4}\big[8(8x^2-5)-48x(2x-5)\big]. …

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