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Exercise 10.3 · Q9

Q.Differentiate the following: f(t)=1+tan⁡t3f(t) = \sqrt[3]{1+\tan t}

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Step 1. Let u=1+tan⁡tu=1+\tan t, so f=u1/3f=u^{1/3}.

Step 2. dfdu=13u−2/3\dfrac{df}{du}=\dfrac13u^{-2/3}, dudt=sec⁡2t\dfrac{du}{dt}=\sec^2 t.

Step 3. Chain rule: f′(t)=13(1+tan⁡t)−2/3sec⁡2tf'(t)=\dfrac13(1+\tan t)^{-2/3}\sec^2 t. …

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