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Exercise 10.3 · Q27

Q.Differentiate the following: y=excos⁡xy = e^{x\cos x}

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Step 1. Let u=xcos⁡xu=x\cos x, so y=euy=e^u.

Step 2. dydu=eu\dfrac{dy}{du}=e^u.

Step 3. Differentiate u=xcos⁡xu=x\cos x using the product rule: dudx=1⋅cos⁡x+x⋅(−sin⁡x)=cos⁡x−xsin⁡x\dfrac{du}{dx}=1\cdot\cos x+x\cdot(-\sin x)=\cos x-x\sin x. …

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