Skip to content
Exercise 9.1 · Q1
Q.

Complete the table using a calculator and use the result to estimate the limit.

lim⁡x→2x−2x2−x−2\lim_{x\to2}\dfrac{x-2}{x^2-x-2}

xx1.91.91.991.991.9991.9992.0012.0012.012.012.12.1
f(x)f(x)
Puducherry TnboardTextbookSubjectiveImportance★★★★★
1% · 1/144 Questions
✓ Free question

Step 1. Try direct substitution. Putting x=2x=2 into x−2x2−x−2\dfrac{x-2}{x^2-x-2} gives 00\dfrac{0}{0}, an indeterminate form, so the expression must first be simplified.

Step 2. Factor the denominator. x2−x−2=(x−2)(x+1)x^2-x-2=(x-2)(x+1), so for x≠2x\ne2,

x−2x2−x−2=x−2(x−2)(x+1)=1x+1.\dfrac{x-2}{x^2-x-2}=\dfrac{x-2}{(x-2)(x+1)}=\dfrac1{x+1}.

Step 3. Fill the table using f(x)=1x+1f(x)=\dfrac1{x+1} (equivalent to the original for x≠2x\ne2).

xx1.91.91.991.991.9991.9992.0012.0012.012.012.12.1
f(x)f(x)0.34480.34480.33440.33440.33340.33340.33320.33320.33220.33220.32260.3226

As x→2−x\to2^- and x→2+x\to2^+, the values both trend toward 0.3333…0.3333\ldots

Step 4. Confirm algebraically. lim⁡x→21x+1=12+1=13\displaystyle\lim_{x\to2}\dfrac1{x+1}=\dfrac1{2+1}=\dfrac13, matching the table.

✓Final answer

lim⁡x→2x−2x2−x−2=13\displaystyle\lim_{x\to2}\dfrac{x-2}{x^2-x-2}=\boxed{\dfrac13}

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.