Skip to content
Exercise 9.1 · Q9

Q.Use the graph (Fig. 9.15) to find the limit, if it exists. If the limit does not exist, explain why.
[!FORMULA] lim⁡x→2f(x),where f(x)={4−x,x≠20,x=2\lim_{x\to2}f(x),\qquad \text{where } f(x)=\begin{cases}4-x, & x\ne2\\ 0, & x=2\end{cases}

Graph of f(x) = 4 - x for x != 2 (a straight line slope -1, y-intercept 4) with an OPEN circle at (2, 2) (the value the line would take) — Mathematics question
Figure
Puducherry TnboardTextbookSubjectiveImportance★★★★★
6% · 9/144 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Read the definition/graph. Fig. 9.15 shows the line y=4−xy=4-x with an open (hollow) circle at (2,2)(2,2) — the height the line approaches — and a separate filled dot at (2,0)(2,0), the actual value f(2)=0f(2)=0 prescribed by the piecewise rule.

Step 2. Use the branch that governs values near x=2x=2. For all x≠2x\ne2 (both x→2−x\to2^- and x→2+x\to2^+), f(x)=4−xf(x)=4-x.

Step 3. Take the limit of that branch. lim⁡x→2(4−x)=4−2=2\displaystyle\lim_{x\to2}(4-x)=4-2=2. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.