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Exercise 9.1 · Q2
Q.

Complete the table using a calculator and use the result to estimate the limit.

lim⁡x→2x−2x2−4\lim_{x\to2}\dfrac{x-2}{x^2-4}

xx1.91.91.991.991.9991.9992.0012.0012.012.012.12.1
f(x)f(x)
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✓ Free question

Step 1. Try direct substitution. At x=2x=2, x−2x2−4=00\dfrac{x-2}{x^2-4}=\dfrac00, indeterminate.

Step 2. Factor. x2−4=(x−2)(x+2)x^2-4=(x-2)(x+2), so for x≠2x\ne2,

x−2x2−4=x−2(x−2)(x+2)=1x+2.\dfrac{x-2}{x^2-4}=\dfrac{x-2}{(x-2)(x+2)}=\dfrac1{x+2}.

Step 3. Table (using f(x)=1x+2f(x)=\dfrac1{x+2} for x≠2x\ne2).

xx1.91.91.991.991.9991.9992.0012.0012.012.012.12.1
f(x)f(x)0.25640.25640.25060.25060.25010.25010.24990.24990.24940.24940.24390.2439

Both sides trend to 0.250.25.

Step 4. Confirm algebraically. lim⁡x→21x+2=14\displaystyle\lim_{x\to2}\dfrac1{x+2}=\dfrac1{4}.

✓Final answer

lim⁡x→2x−2x2−4=14\displaystyle\lim_{x\to2}\dfrac{x-2}{x^2-4}=\boxed{\dfrac14}

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