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Exercise 11.1 · Q3

Q.Integrate the following with respect to xx:

(i) 12312^{3}
(ii) x24x25\dfrac{x^{24}}{x^{25}}
(iii) exe^{x}
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Part (i)'s integrand is a pure numeric constant once evaluated; part (ii) collapses to 1/x1/x by the laws of exponents; part (iii) is already a standard form.

Step 1. Part (i). 123=12×12×12=172812^3=12\times12\times12=1728 is a constant, so this is ∫k dx=kx+c\int k\,dx=kx+c with k=1728k=1728.

∫123 dx=1728x+c.\int 12^3\,dx = 1728x+c.

Step 2. Part (ii). By the laws of exponents, x24x25=x24−25=x−1=1x\dfrac{x^{24}}{x^{25}}=x^{24-25}=x^{-1}=\dfrac1x, and ∫1x dx=log⁡∣x∣+c\int\dfrac1x\,dx=\log|x|+c (the excluded n=−1n=-1 case of the power rule).

∫x24x25 dx=log⁡∣x∣+c.\int\frac{x^{24}}{x^{25}}\,dx=\log|x|+c. …

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