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Exercise 11.13 · Q6

Q.∫tan⁡xsin⁡2x dx\displaystyle\int \dfrac{\sqrt{\tan x}}{\sin 2x}\,dx is

(1) tan⁡x+c\sqrt{\tan x}+c
(2) 2tan⁡x+c2\sqrt{\tan x}+c
(3) 12tan⁡x+c\dfrac12\sqrt{\tan x}+c
(4) 14tan⁡x+c\dfrac14\sqrt{\tan x}+c
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Substitute t=tan⁡xt=\tan x and rewrite sin⁡2x\sin 2x in terms of tt.

Step 1. Put t=tan⁡xt=\tan x, so dt=sec⁡2x dx=dxcos⁡2xdt=\sec^2x\,dx=\dfrac{dx}{\cos^2x}. Also sin⁡2x=2sin⁡xcos⁡x=2tcos⁡2x\sin2x=2\sin x\cos x=2t\cos^2x. …

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