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Exercise 11.13 · Q11

Q.∫23x+5 dx\displaystyle\int 2^{3x+5}\,dx is

(1) 3(23x+5)log⁡2+c\dfrac{3(2^{3x+5})}{\log 2}+c
(2) 23x+52log⁡(3x+5)+c\dfrac{2^{3x+5}}{2\log(3x+5)}+c
(3) 23x+52log⁡3+c\dfrac{2^{3x+5}}{2\log 3}+c
(4) 23x+53log⁡2+c\dfrac{2^{3x+5}}{3\log 2}+c
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Apply the linear-exponent exponential rule ∫akx+bdx=akx+b/(klog⁡a)\int a^{kx+b}dx=a^{kx+b}/(k\log a).

Step 1. Use ∫akx+b dx=akx+bklog⁡a+c\int a^{kx+b}\,dx=\dfrac{a^{kx+b}}{k\log a}+c with a=2a=2, k=3k=3, b=5b=5. …

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