Skip to content
Exercise 11.4 · Q1

Q.If f′(x)=4x−5f'(x) = 4x-5 and f(2)=1f(2)=1, find f(x)f(x).

Puducherry TnboardTextbookSubjectiveImportance★★★★★
12% · 16/129 Questions
✓ Free question

Integrate both sides of f′(x)=4x−5f'(x)=4x-5 with respect to xx to recover f(x)f(x) up to an arbitrary constant, then substitute the given point f(2)=1f(2)=1 to determine that constant.

Step 1. Integrate f′(x)f'(x).

f(x)=∫(4x−5) dx=2x2−5x+c.f(x) = \int (4x-5)\,dx = 2x^2-5x+c.

Step 2. Apply the given condition f(2)=1f(2)=1.

f(2)=2(2)2−5(2)+c=8−10+c=−2+c.f(2) = 2(2)^2-5(2)+c = 8-10+c=-2+c.

Setting this equal to 11: −2+c=1⇒c=3-2+c=1 \Rightarrow c=3.

Step 3. Final answer.

f(x)=2x2−5x+3.f(x) = 2x^2-5x+3.

Step 4. Check. f′(x)=ddx(2x2−5x+3)=4x−5f'(x)=\dfrac{d}{dx}(2x^2-5x+3)=4x-5 ✓, and f(2)=2(4)−10+3=8−10+3=1f(2)=2(4)-10+3=8-10+3=1 ✓ — both the derivative and the point condition are satisfied.

✓Final answer

f(x)=2x2−5x+3f(x)=2x^{2}-5x+3

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.