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Exercise 11.4 · Q2

Q.If f′(x)=9x2−6xf'(x) = 9x^{2}-6x and f(0)=−3f(0)=-3, find f(x)f(x).

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✓ Free question

Integrate both sides of f′(x)=9x2−6xf'(x)=9x^2-6x with respect to xx, then substitute the given point f(0)=−3f(0)=-3 to solve for the constant of integration.

Step 1. Integrate f′(x)f'(x) termwise.

f(x)=∫(9x2−6x) dx=9⋅x33−6⋅x22+c=3x3−3x2+c.f(x) = \int (9x^2-6x)\,dx = 9\cdot\frac{x^3}{3}-6\cdot\frac{x^2}{2}+c = 3x^3-3x^2+c.

Step 2. Apply the given condition f(0)=−3f(0)=-3.

f(0)=3(0)3−3(0)2+c=c.f(0) = 3(0)^3-3(0)^2+c = c.

Setting this equal to −3-3: c=−3c=-3.

Step 3. Final answer.

f(x)=3x3−3x2−3.f(x) = 3x^3-3x^2-3.

✓Final answer

f(x)=3x3−3x2−3f(x)=3x^{3}-3x^{2}-3

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