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Question 102 of 129

Q.Find the separate equations of straight lines from a combined equation 2x2+xy−3y2=02x^2+xy-3y^2=0.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2019Subjective· 2mImportance★★★★★
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2x2+xy−3y22x^2+xy-3y^2 factors as (2x+3y)(x−y)(2x+3y)(x-y), so the combined equation represents the pair of lines 2x+3y=02x+3y=0 and x−y=0x-y=0.

A homogeneous second-degree equation ax2+hxy+by2=0ax^2+hxy+by^2=0 always factors into two linear equations (real or imaginary) through the origin.

Here, look for a factorization 2x2+xy−3y2=(2x+3y)(x−y)2x^2+xy-3y^2 = (2x+3y)(x-y). Verify: (2x+3y)(x−y)=2x2−2xy+3xy−3y2=2x2+xy−3y2(2x+3y)(x-y) = 2x^2-2xy+3xy-3y^2 = 2x^2+xy-3y^2. ✓ Matches.

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