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Question 112 of 129

Q.The points lie on the locus of 3x2+3y2−8x−12y+17=03x^2 + 3y^2 - 8x - 12y + 17 = 0.

(a) (1, 2)
(b) (0, 0)
(c) (0, -1)
(d) (-2, 3)
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023MCQ· 1mImportance★★★★★
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Substitute each option into the equation; the point that makes it exactly zero lies on the curve.

Test (1,2)(1,2): 3(1)2+3(2)2−8(1)−12(2)+17=3+12−8−24+17=03(1)^2+3(2)^2-8(1)-12(2)+17 = 3+12-8-24+17 = 0. ✓ It satisfies the equation.

Test (0,0)(0,0): 0+0−0−0+17=17≠00+0-0-0+17=17\ne 0. ✗

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