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Question 81 of 113

Q.Find the vectors of magnitude 5 units, which are parallel to the vector 2i⃗−j⃗2\vec{i} - \vec{j}.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2018Subjective· 3mImportance★★★★★
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Scaling the unit vector along 2i⃗−j⃗2\vec i-\vec j by magnitude 5 (in either direction) gives ±(25 i⃗−5 j⃗)\pm(2\sqrt5\,\vec i-\sqrt5\,\vec j).

The given vector is v⃗=2i⃗−j⃗\vec v = 2\vec i - \vec j, with magnitude ∣v⃗∣=22+(−1)2=4+1=5|\vec v| = \sqrt{2^2+(-1)^2} = \sqrt{4+1} = \sqrt5.

The unit vector along v⃗\vec v is v^=v⃗∣v⃗∣=2i⃗−j⃗5\hat v = \dfrac{\vec v}{|\vec v|} = \dfrac{2\vec i-\vec j}{\sqrt5}.

A vector of magnitude 5 parallel to v⃗\vec v is 5v^=5(2i⃗−j⃗)5=5(2i⃗−j⃗)=25 i⃗−5 j⃗5\hat v = \dfrac{5(2\vec i-\vec j)}{\sqrt5} = \sqrt5(2\vec i-\vec j) = 2\sqrt5\,\vec i - \sqrt5\,\vec j.

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