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Question 98 of 113

Q.Find the area of the parallelogram whose adjacent sides are a⃗=3i^+j^+4k^\vec a = 3\hat i + \hat j + 4\hat k and b⃗=i^−j^+k^\vec b = \hat i - \hat j + \hat k.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023Subjective· 3mImportance★★★★★
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Computing the cross product a⃗×b⃗\vec a\times\vec b and its magnitude gives the parallelogram's area as 42\sqrt{42}.

Given a⃗=3i^+j^+4k^\vec a = 3\hat i+\hat j+4\hat k, b⃗=i^−j^+k^\vec b=\hat i-\hat j+\hat k:

a⃗×b⃗=∣i^j^k^3141−11∣\vec a\times\vec b = \begin{vmatrix}\hat i&\hat j&\hat k\\3&1&4\\1&-1&1\end{vmatrix}

=i^(1⋅1−4⋅(−1))−j^(3⋅1−4⋅1)+k^(3⋅(−1)−1⋅1)= \hat i(1\cdot1-4\cdot(-1)) - \hat j(3\cdot1-4\cdot1) + \hat k(3\cdot(-1)-1\cdot1)

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