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I. Multiple Choice Questions · Q2

Q.If the error in the measurement of radius is 2%, then the error in the determination of volume of the sphere will be

(a) 8%
(b) 2%
(c) 4%
(d) 6%
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✓ Free question

Step 1. Volume of a sphere: V=43πr3V=\dfrac43\pi r^3.

Step 2. By the power rule for error propagation, ΔVV=3Δrr\dfrac{\Delta V}{V}=3\dfrac{\Delta r}{r}.

Step 3. Given Δrr×100=2%\dfrac{\Delta r}{r}\times100=2\%, so ΔVV×100=3×2%=6%\dfrac{\Delta V}{V}\times100=3\times2\%=6\%.

✓Final answer

(d) 6%

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