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Question 56 of 66

Q.A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns from B to A after another 3 s. The time period is :

(a) 12 s
(b) 15 s
(c) 9 s
(d) 6 s
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023MCQ· 1mImportance★★★★★
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Using the standard SHM result T = 2(t1 + t2) for two crossings made with equal speed, T = 2(3+3) = 12 s.

When a particle executing SHM passes through two points A and B with equal speed, it reaches from A to B in two complementary ways: directly (taking time t1), and by continuing on through the nearer extreme position and coming back round to complete the journey from B to A (taking time t2), so that together the two times account for exactly half of a full oscillation cycle in a specific standard way.

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