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IV. Exercises · Q5

Q.The reading of pressure meter attached with a closed pipe is 5×1055\times10^{5} N m−2^{-2}. On opening the valve of the pipe, the reading of the pressure meter is 4.5×1054.5\times10^{5} N m−2^{-2}. Calculate the speed of the water flowing in the pipe.

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Step 1. With the valve closed, the water in the pipe is at rest, so its measured pressure is the static pressure, P1=5×105P_1=5\times10^5 N m−2^{-2}, with v1=0v_1=0.

Step 2. With the valve open, water flows at speed v and the gauge reads the lower pressure P2=4.5×105P_2=4.5\times10^5 N m−2^{-2}.

Step 3. Applying Bernoulli's equation between the two states (same height, so potential-energy terms cancel): P1+12ρ(0)2=P2+12ρv2⇒P1−P2=12ρv2P_1+\tfrac12\rho(0)^2=P_2+\tfrac12\rho v^2\Rightarrow P_1-P_2=\tfrac12\rho v^2. …

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