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Question 57 of 58

Q.XeF6XeF_6 on complete hydrolysis produces :

(a) XeO3XeO_3
(b) XeOF4XeOF_4
(c) XeO2XeO_2
(d) XeO2F2XeO_2F_2
Puducherry TnboardTamil Nadu HSC (DGE) Board 2026MCQ· 1mImportance★★★★★
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When XeF6XeF_6 is completely hydrolysed by excess water, every Xe−FXe-F bond is replaced, converting the six fluorine atoms into three oxygen atoms (each doubly bonded), giving xenon trioxide.

Xenon hexafluoride reacts readily with water; the extent of hydrolysis depends on the amount of water used:

  • Partial hydrolysis (limited water) gives an oxyfluoride: XeF6+H2O→XeOF4+2HFXeF_6 + H_2O \rightarrow XeOF_4 + 2HF XeF6+2H2O→XeO2F2+4HFXeF_6 + 2H_2O \rightarrow XeO_2F_2 + 4HF
  • Complete hydrolysis (excess water) replaces all six fluorine atoms, giving the fully oxygenated compound, xenon trioxide, along with hydrofluoric acid: XeF6+3H2O→XeO3+6HFXeF_6 + 3H_2O \rightarrow XeO_3 + 6HF …

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