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Mathematics · Ch 9 — Applications of Integration

Improper Integrals

9.5

Improper Integrals

The Riemann integral ∫abf(x) dx\int_a^b f(x)\,dx (§9.2.1) requires the interval [a,b][a,b] to be finite and f(x)f(x) to be finite at every point of [a,b][a,b]. Many physical applications instead need integrals of the shape

∫a∞f(x) dx,∫−∞af(x) dx,∫−∞∞f(x) dx,\int_a^\infty f(x)\,dx,\qquad \int_{-\infty}^a f(x)\,dx,\qquad \int_{-\infty}^\infty f(x)\,dx,

where aa is real and ff is continuous on the interval of integration. These are called improper integrals of the first kind, and are defined as limits of ordinary (proper) Riemann integrals:

(i) ∫a∞f(x) dx=lim⁡t→∞∫atf(x) dx(ii) ∫−∞af(x) dx=lim⁡t→−∞∫taf(x) dx(iii) ∫−∞∞f(x) dx=lim⁡t→∞∫−ttf(x) dx.\text{(i)}\ \int_a^\infty f(x)\,dx=\lim_{t\to\infty}\int_a^t f(x)\,dx \qquad \text{(ii)}\ \int_{-\infty}^a f(x)\,dx=\lim_{t\to-\infty}\int_t^a f(x)\,dx \qquad \text{(iii)}\ \int_{-\infty}^\infty f(x)\,dx=\lim_{t\to\infty}\int_{-t}^t f(x)\,dx.

If the relevant limit exists (is finite), the improper integral is said to converge; otherwise it diverges.

Practical evaluation. By the Second Fundamental Theorem, there is a function F(t)F(t) with ∫atf(x) dx=F(t)−F(a)\int_a^t f(x)\,dx=F(t)-F(a), so ∫a∞f(x) dx=lim⁡t→∞[F(t)−F(a)]\displaystyle\int_a^\infty f(x)\,dx=\lim_{t\to\infty}\big[F(t)-F(a)\big] — find the ordinary anti-derivative, substitute tt for the infinite endpoint, and take the limit afterward.

Worked pattern (Example 9.35). ∫0∞1a2+x2 dx=[1atan⁡−1xa]0∞=1a(π2−0)=π2a\displaystyle\int_0^\infty\dfrac{1}{a^2+x^2}\,dx=\left[\dfrac1a\tan^{-1}\dfrac xa\right]_0^\infty=\dfrac1a\left(\dfrac\pi2-0\right)=\dfrac{\pi}{2a} (using lim⁡x→∞tan⁡−1x=π2\lim_{x\to\infty}\tan^{-1}x=\frac\pi2); and, since 1a2+x2\frac1{a^2+x^2} is even, ∫−∞∞dxa2+x2=2∫0∞dxa2+x2=πa\displaystyle\int_{-\infty}^\infty\dfrac{dx}{a^2+x^2}=2\int_0^\infty\dfrac{dx}{a^2+x^2}=\dfrac{\pi}{a}. …