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Exercise 2.7 · Q2

Q.Find the rectangular form of the complex numbers

(i) (cos⁡π6+isin⁡π6)(cos⁡π12+isin⁡π12)\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)\left(\cos\dfrac\pi{12}+i\sin\dfrac\pi{12}\right)
(ii) cos⁡π6−isin⁡π62(cos⁡π3+isin⁡π3)\dfrac{\cos\frac\pi6-i\sin\frac\pi6}{2\left(\cos\frac\pi3+i\sin\frac\pi3\right)}.
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Both products are already given in polar form, so we simply combine the angles using the product/quotient rules of Property 2/3 (§2.7.3) and then expand the resulting single cis expression into rectangular form.

Step 1. Part (i): identify the angles. (cos⁡π6+isin⁡π6)=cis⁡π6\left(\cos\frac\pi6+i\sin\frac\pi6\right)=\operatorname{cis}\dfrac\pi6 and (cos⁡π12+isin⁡π12)=cis⁡π12\left(\cos\frac\pi{12}+i\sin\frac\pi{12}\right)=\operatorname{cis}\dfrac\pi{12}.

Step 2. Part (i): multiply using cis⁡θ1⋅cis⁡θ2=cis⁡(θ1+θ2)\operatorname{cis}\theta_1\cdot\operatorname{cis}\theta_2=\operatorname{cis}(\theta_1+\theta_2).

cis⁡π6⋅cis⁡π12=cis⁡(π6+π12)=cis⁡(2π+π12)=cis⁡3π12=cis⁡π4.\operatorname{cis}\frac\pi6\cdot\operatorname{cis}\frac\pi{12}=\operatorname{cis}\left(\frac\pi6+\frac\pi{12}\right)=\operatorname{cis}\left(\frac{2\pi+\pi}{12}\right)=\operatorname{cis}\frac{3\pi}{12}=\operatorname{cis}\frac\pi4.

Step 3. Part (i): expand to rectangular form.

cis⁡π4=cos⁡π4+isin⁡π4=22+i22.\operatorname{cis}\frac\pi4=\cos\frac\pi4+i\sin\frac\pi4=\frac{\sqrt2}2+i\frac{\sqrt2}2.

Step 4. Part (ii): rewrite the numerator as a single cis. cos⁡π6−isin⁡π6=cos⁡(−π6)+isin⁡(−π6)=cis⁡(−π6)\cos\frac\pi6-i\sin\frac\pi6=\cos\left(-\frac\pi6\right)+i\sin\left(-\frac\pi6\right)=\operatorname{cis}\left(-\frac\pi6\right) (using the corollary (cos⁡θ−isin⁡θ)=cis⁡(−θ)(\cos\theta-i\sin\theta)=\operatorname{cis}(-\theta)). The denominator is 2cis⁡π32\operatorname{cis}\dfrac\pi3.

Step 5. Part (ii): divide using cis⁡θ1cis⁡θ2=cis⁡(θ1−θ2)\dfrac{\operatorname{cis}\theta_1}{\operatorname{cis}\theta_2}=\operatorname{cis}(\theta_1-\theta_2).

cis⁡(−π6)2cis⁡π3=12cis⁡(−π6−π3)=12cis⁡(−π+2π6)=12cis⁡(−3π6)=12cis⁡(−π2).\frac{\operatorname{cis}\left(-\frac\pi6\right)}{2\operatorname{cis}\frac\pi3}=\frac12\operatorname{cis}\left(-\frac\pi6-\frac\pi3\right)=\frac12\operatorname{cis}\left(-\frac{\pi+2\pi}{6}\right)=\frac12\operatorname{cis}\left(-\frac{3\pi}6\right)=\frac12\operatorname{cis}\left(-\frac\pi2\right).

Step 6. Part (ii): expand to rectangular form.

12cis⁡(−π2)=12(cos⁡(−π2)+isin⁡(−π2))=12(0−i)=−i2.\frac12\operatorname{cis}\left(-\frac\pi2\right)=\frac12\left(\cos\left(-\frac\pi2\right)+i\sin\left(-\frac\pi2\right)\right)=\frac12(0-i)=-\frac i2.

✓Final answer

(i) 22+i22\dfrac{\sqrt2}2+i\dfrac{\sqrt2}2 (ii) −i2-\dfrac i2.

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