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Question 54 of 84

Q.The order of [7][7] in (Z9,+9)(Z_9, +_9) is :

(a) 9
(b) 6
(c) 3
(d) 1
Puducherry TnboardTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★
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In the cyclic group (Zn,+n)(\mathbb Z_n,+_n), the order of element [k][k] equals n/gcd⁡(k,n)n/\gcd(k,n); here n=9,k=7n=9,k=7 are coprime, so [7][7] generates the whole group and has order 99.

  1. (Z9,+9)={[0],[1],…,[8]}(\mathbb Z_9,+_9)=\{[0],[1],\dots,[8]\} is the cyclic group of integers modulo 9 under addition, of order 9.
  2. For a cyclic group of order nn generated by [1][1], the order of the element [k][k] is ngcd⁡(k,n)\dfrac{n}{\gcd(k,n)}.
  3. Here k=7k=7, n=9n=9. Compute gcd⁡(7,9)\gcd(7,9): since 7 is prime and does not divide 9, gcd⁡(7,9)=1\gcd(7,9)=1.
  4. So order of [7]=91=9[7] = \dfrac{9}{1}=9. …

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