Skip to content
Question 82 of 84

Q.The dual of ¬(p∨q)∨[p∨(p∧¬r)]\lnot(p\vee q)\vee[p\vee(p\wedge\lnot r)] is :

(a) ¬(p∧q)∧[p∧(p∧r)]\lnot(p\wedge q)\wedge[p\wedge(p\wedge r)]
(b) ¬(p∧q)∧[p∨(p∧¬r)]\lnot(p\wedge q)\wedge[p\vee(p\wedge\lnot r)]
(c) ¬(p∧q)∧[p∧(p∨¬r)]\lnot(p\wedge q)\wedge[p\wedge(p\vee\lnot r)]
(d) (p∧q)∧[p∧(p∨¬r)](p\wedge q)\wedge[p\wedge(p\vee\lnot r)]
Puducherry TnboardTamil Nadu HSC (DGE) Board 2026MCQ· 1mImportance★★★★★
98% · 82/84 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The dual of a statement is formed by interchanging every ∧\wedge with ∨\vee (and TT with FF) throughout the formula, while leaving negations on the propositional variables themselves unchanged.

  1. The given statement is ¬(p∨q)∨[p∨(p∧¬r)]\lnot(p\vee q)\vee\left[p\vee(p\wedge\lnot r)\right], which has three occurrences of connectives to dualize: the ∨\vee inside ¬(p∨q)\lnot(p\vee q), the outer ∨\vee joining the two bracketed parts, and the ∨,∧\vee,\wedge inside [p∨(p∧¬r)]\left[p\vee(p\wedge\lnot r)\right].
  2. Dualize ¬(p∨q)\lnot(p\vee q): swap the inner ∨\vee to ∧\wedge, giving ¬(p∧q)\lnot(p\wedge q) (the negation itself is left in place — only ∧/∨\wedge/\vee are swapped, never the variables or their own negations). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.