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Question 77 of 84

Q.(a) Prove that p→(¬q∨r)≡¬p∨(¬q∨r)p\to(\lnot q\vee r)\equiv \lnot p\vee(\lnot q\vee r) using truth table. OR

(b) Suppose a person deposits ₹ 10,000 in a bank account at the rate of 5% per annum compounded continuously. How much money will be in his bank account 18 months later ?
Puducherry TnboardTamil Nadu HSC (DGE) Board 2023Subjective· 5mImportance★★★★★
92% · 77/84 Questions
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(a) Builds the 8-row truth table (for p,q,rp,q,r) for both p→(¬q∨r)p\to(\lnot q\vee r) and ¬p∨(¬q∨r)\lnot p\vee(\lnot q\vee r) and confirms they agree everywhere; (b) applies the continuous-compounding formula A=PertA=Pe^{rt} with t=1.5t=1.5 years. Both alternatives answered below.

(a) Prove p→(¬q∨r)≡¬p∨(¬q∨r)p\to(\lnot q\vee r)\equiv\lnot p\vee(\lnot q\vee r) by truth table

1. Recall the implication law. For any statements A,BA,B: A→B≡¬A∨BA\to B\equiv\lnot A\vee B. Here A=pA=p and B=(¬q∨r)B=(\lnot q\vee r), so the two sides should automatically agree — the truth table confirms it explicitly.

2. Full truth table (T=true, F=false):

ppqqrr¬q\lnot q¬q∨r\lnot q\vee rp→(¬q∨r)p\to(\lnot q\vee r)¬p\lnot p¬p∨(¬q∨r)\lnot p\vee(\lnot q\vee r)
TTTFTTFT
TTFFFFFF
TFTTTTFT
TFFTTTFT
FTTFTTTT
FTFFFTTT
FFTTTTTT
FFFTTTTT

3. Compare the last two columns. In every one of the 88 rows, p→(¬q∨r)p\to(\lnot q\vee r) has the same truth value as ¬p∨(¬q∨r)\lnot p\vee(\lnot q\vee r).

4. Conclusion. Since the truth tables are identical row-for-row, p→(¬q∨r)≡¬p∨(¬q∨r)p\to(\lnot q\vee r)\equiv\lnot p\vee(\lnot q\vee r).

(b) Continuous compounding

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