In Thomson's experiment for the determination of $(e/m)$ of electron, electric field of intensity 'E' only is applied. Now the deflection produced by the electron beam is directly proportional to : (a) $E^2$ (b) $E$ (c) $E^{-2}$ (d) $E^{-1}$

In Thomson's experiment for the determination of (e/m) of electron, electric field of intensity 'E' only is ap

Question 68 of 96

(e/m)

(a)

E^2

(b)

E

(c)

E^{-2}

(d)

E^{-1}

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The deflection of the electron beam, with only the electric field $E$ applied, is directly proportional to $E$ .

In Thomson's $e/m$ experiment, when a transverse electric field of intensity $E$ alone is applied between the deflecting plates, each electron in the beam experiences a constant transverse electric force $F = eE$ , producing a transverse acceleration $a = \dfrac{eE}{m}$ .

If the electrons enter with a fixed horizontal speed $v$ and traverse plates of length $l$ , the time spent between the plates is $t = \dfrac{l}{v}$ . The vertical (transverse) deflection acquired while crossing the plates is:

$y = \dfrac12 a t^2 = \dfrac12 \cdot \dfrac{eE}{m}\cdot\left(\dfrac{l}{v}\right)^2$

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Q.In Thomson's experiment for the determination of $(e/m)$ of electron, electric field of intensity 'E' only is applied. Now the deflection produced by the electron beam is directly proportional to :

Concept understanding — Thomson e/m Determination

Q.In Thomson's experiment for the determination of (e/m)(e/m)(e/m) of electron, electric field of intensity 'E' only is applied. Now the deflection produced by the electron beam is directly proportional to :

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Q.In Thomson's experiment for the determination of $(e/m)$ of electron, electric field of intensity 'E' only is applied. Now the deflection produced by the electron beam is directly proportional to :

Unlock everything free for 14 days