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NCERT Exemplar · Q37

Q.Explain the shape of BrF5.

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The shape of BrF5 is square pyramidal, determined by 7 valence electrons on Br, 5 bond pairs with F, and 1 lone pair occupying an equatorial position in a trigonal bipyramidal electron geometry.

The key to predicting molecular shape is to start with the Lewis dot structure — not memorising shapes, but building them from first principles. For BrF5, we need to count electrons, arrange them, and then let VSEPR theory tell us the geometry.

Bromine is in group 17, so it has 7 valence electrons. Each fluorine also has 7, and there are five of them. Total valence electrons: 7+5×7=427 + 5 \times 7 = 42 electrons. In the Lewis structure, bromine forms five single bonds to the five fluorine atoms, using up 5×2=105 \times 2 = 10 electrons. The remaining 42−10=3242 - 10 = 32 electrons are placed as lone pairs — three on each fluorine (that’s 5×6=305 \times 6 = 30 electrons), leaving 2 electrons as one lone pair on bromine.

So bromine has 5 bond pairs and 1 lone pair — a total of 6 electron domains around it.

  1. Electron domain geometry: With 6 electron domains, the repulsion between them is minimised when they point to the corners of an octahedron. This is the parent geometry — octahedral electron pair geometry.

  2. Lone pair placement: In an octahedral arrangement, all positions are equivalent? Not quite. If you place the lone pair at any vertex, the resulting molecular shape is the same — square pyramidal. Why? Because the lone pair repels more strongly than a bond pair, so it pushes the five bond pairs slightly away, distorting the octahedron. The five fluorine atoms end up at four corners of a square (the base) and one above the plane (the apex), with the lone pair occupying the sixth octahedral position opposite the apex.

  3. Molecular shape: The shape described by the positions of the atoms (ignoring the lone pair) is a square pyramid. The bromine atom sits slightly below the centre of the square base (pushed by the lone pair), and the apical fluorine is directly above.

Watch out

A common mistake is to think BrF5 is trigonal bipyramidal because Br has 5 bonds. But the lone pair counts as a domain too — 6 domains means octahedral electron geometry, not trigonal bipyramidal. The lone pair is NOT "invisible" to VSEPR. …

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