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NCERT Exemplar · Q31

Q.A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process of expansion and compression as shown in Fig. 6.1. What will be the value of ΔH\Delta H for the cycle as a whole?

Fig. 6.1 — cyclic process on a pressure-volume plot: from point 1 the gas expands along a curve to point 2, is compressed at constant pressure from 2 to 3, and returns at constant volume from 3 to 1
Figure 6.1
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Enthalpy is a state function, so for any cyclic process that returns the system to its initial state, the change in enthalpy must be zero. ΔH=0\Delta H = 0 for the complete cycle.

Why enthalpy change vanishes in a cycle

Enthalpy HH is a state function, meaning its value depends only on the current state of the system (pressure, temperature, composition) and not on the path taken to reach that state. This is the central insight.

When a system undergoes a cyclic process, it traces some path through different states but ultimately returns to exactly where it started: same pressure, same temperature, same volume, same everything. Because HH depends only on the state, and the initial and final states are identical, the change in enthalpy around the complete cycle must be:

ΔHcycle=Hfinal−Hinitial=Hinitial−Hinitial=0\Delta H_{\text{cycle}} = H_{\text{final}} - H_{\text{initial}} = H_{\text{initial}} - H_{\text{initial}} = 0

This reasoning applies to any state function—internal energy UU, Gibbs free energy GG, entropy SS (for a reversible cycle), etc.

Step-by-step reasoning

  1. Identify what changes during the cycle.

    The gas expands and compresses through various intermediate states. At different points in the cycle, PP, VV, and TT all vary. The enthalpy at each intermediate point is different.

  2. Recognize the defining property of a cycle.

    The process is cyclic: the gas returns to its initial state. Every thermodynamic property that defines the state—pressure, volume, temperature, and therefore enthalpy—has the same value at the end as at the beginning.

  3. Apply the state-function property.

    For a state function, only the endpoints matter:

ΔH=∫ifdH=Hf−Hi\Delta H = \int_{i}^{f} dH = H_f - H_i

Since Hf=HiH_f = H_i for a cycle, we have ΔH=0\Delta H = 0.

  1. Check independence from path details. …

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