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NCERT Exemplar · Q54

Q.Match the following :
Column I

(i) Entropy of vapourisation
(ii) K for spontaneous process
(iii) Crystalline solid state
(iv) ΔU in adiabatic expansion of ideal gas
Column II
(a) decreases
(b) is always positive
(c) lowest entropy
(d) ΔHvap/Tb
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Match thermodynamic properties with their characteristics: vaporization entropy relates to enthalpy and boiling point, spontaneity connects to equilibrium constants, crystal order determines entropy, and adiabatic expansion affects internal energy. The matches are (i)→(b),(d) · (ii)→(b) · (iii)→(c) · (iv)→(a).

The heart of this matching exercise lies in understanding how entropy, spontaneity, and energy behave in different thermodynamic contexts. Each item in Column I represents a fundamental concept whose behavior or value follows from first principles.

Concept: Connecting Thermodynamic Quantities

Entropy measures disorder. Phase transitions, equilibrium positions, structural order, and energy changes all leave signatures in entropy and related quantities. The key is recognizing what each process or state implies about the underlying thermodynamics.


Step-by-Step Matching

1. Entropy of vaporization → (b) is always positive, and (d) ΔHvap/Tb\Delta H_{\text{vap}}/T_b

Vaporisation always increases disorder, so ΔSvap\Delta S_{vap} is always positive — and its value at the boiling point is ΔHvap/Tb\Delta H_{vap}/T_b:

When a liquid vaporizes at its boiling point, the process occurs reversibly at constant temperature and pressure. The entropy change for this phase transition is:

ΔSvap=qrevT=ΔHvapTb\Delta S_{\text{vap}} = \frac{q_{\text{rev}}}{T} = \frac{\Delta H_{\text{vap}}}{T_b}

This is Trouton's rule in its exact form. At the boiling point, the system is in equilibrium between phases, so the heat absorbed divided by the absolute temperature gives the entropy increase as molecules escape into the disordered gas phase.

ΔSvap=ΔHvapTb\Delta S_{\text{vap}} = \frac{\Delta H_{\text{vap}}}{T_b}

2. KK for spontaneous process → (b) is always positive

The equilibrium constant KK is defined as:

ΔG°=−RTln⁡K\Delta G° = -RT \ln K

For a spontaneous process under standard conditions, ΔG°<0\Delta G° < 0, which means ln⁡K>0\ln K > 0, and therefore K>1K > 1. But more fundamentally, KK itself—being a ratio of activities or concentrations raised to positive powers—is always a positive number by definition, regardless of whether the forward or reverse reaction is spontaneous. You cannot have a negative equilibrium constant; it would be physically meaningless.

Watch out

Don't confuse "KK is positive" with "K>1K > 1". The statement here is about the sign: equilibrium constants are always positive real numbers, never negative or zero.

3. Crystalline solid state → (c) lowest entropy

Entropy quantifies the number of accessible microstates. In a perfect crystalline solid at low temperature, atoms or molecules are locked into a highly ordered lattice with minimal positional or orientational freedom. This represents the state of minimum disorder for a substance. …

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