Q.Given that . Then write
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →We are asked to identify two subsets from the set . The subset of even numbers is , and the subset of perfect square numbers is .
When we talk about a "subset," we are looking for a collection of elements that are all part of a larger, original set. The key idea is that every element in the subset must also be an element of the original set. The problem asks us to form subsets based on specific properties: being an even number or being a perfect square number. To do this, we simply examine each element in the given set and check if it satisfies the stated property. If it does, we include it in our new subset.
Let's break this down for each part.
(i) The subset of whose elements are even numbers.
- Understanding "even numbers": An even number is any integer that is exactly divisible by 2. This means it can be written in the form , where is an integer. Examples are , etc.
- Identifying even numbers in : The set is given as . We need to find all numbers in this range that are even.
- The smallest number in is . It is not even.
- The next number is . It is even ().
- The next even number is ().
- This pattern continues, adding each time.
- The largest number in is . Since (with no remainder), is an even number.
- Forming the subset: We collect all these even numbers from . Let's call this subset .
(ii) The subset of whose elements are perfect square numbers.
- Understanding "perfect square numbers": A perfect square number is an integer that can be expressed as the product of an integer with itself. In other words, it is the square of an integer. For example, is a perfect square because , is a perfect square because , is a perfect square because , and so on. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.