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NCERT Exemplar · Q14

Q.Calculate the number of atoms in 39.4 g gold. Molar mass of gold is 197 g mole−1^{-1}.

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Using the mole concept from the Kinetic Theory of Gases, the number of atoms in a given mass is found by converting mass to moles via molar mass, then multiplying by Avogadro’s number. For 39.4 g of gold (molar mass 197 g/mol), the result is 1.204×10231.204 \times 10^{23} atoms.

The Kinetic Theory of Gases gives us a powerful way to think about matter at the atomic scale. It tells us that the number of particles in any sample is proportional to the number of moles, and one mole of any substance always contains the same number of entities — Avogadro’s number, NA=6.022×1023N_A = 6.022 \times 10^{23} mol−1^{-1}. This is the bridge between the macroscopic world we measure (grams) and the microscopic world of atoms.

Gold is a metallic solid, but the mole concept applies universally: whether gas, liquid, or solid, the number of atoms in a sample depends only on the amount of substance in moles. So we start by finding how many moles of gold are in 39.4 g.

  1. Find the number of moles. The molar mass of gold is given as 197 g mol−1^{-1}. That means 1 mole of gold atoms has a mass of 197 g. Number of moles nn is mass divided by molar mass:

n=massmolar mass=39.4 g197 g mol−1n = \frac{\text{mass}}{\text{molar mass}} = \frac{39.4 \text{ g}}{197 \text{ g mol}^{-1}}

n=0.2 moln = 0.2 \text{ mol}

(Check: 197×0.2=39.4197 \times 0.2 = 39.4, so this is exact.)

  1. Convert moles to number of atoms. One mole contains 6.022×10236.022 \times 10^{23} atoms (Avogadro’s number). So the number of atoms NN is:

N=n×NA=0.2×6.022×1023N = n \times N_A = 0.2 \times 6.022 \times 10^{23}

N=1.2044×1023N = 1.2044 \times 10^{23} …

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