NCERT Exemplar · Q20
Q.A rigid, thermally isolated container is divided into two chambers by a partition. The left chamber has volume litre and contains moles of a gas at pressure atm; the right chamber has volume litre and contains moles of the same gas at pressure atm. The partition is removed and the gas is allowed to mix and reach equilibrium. Because the container is isolated, the total internal energy of the gas is conserved. Calculate the pressure of the mixture after equilibrium is reached.
Punjab PsebShort· 3mImportance★★★★★est
78% · 39/50 Questions
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Since the container is isolated, the gas's total internal energy is unchanged when the partition is pulled out. Writing each chamber's energy through and equating the total before and after mixing gives , so atm.
Concept
For an ideal gas the internal energy depends only on temperature: . When the two gas samples mix in an isolated rigid box, no work is done on the surroundings and no heat leaves, so the total internal energy is conserved.
Why this approach
Let the initial temperatures be and and the final common temperature . From the ideal-gas law in each chamber:
Energy conservation ( is the same for the same gas) gives:
Steps
- Apply the ideal-gas law to the whole box after mixing (total moles , total volume ): …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.