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Physics · Ch 6 — System of Particles and Rotational Motion

Angular Acceleration

6.6.1

Angular Acceleration

Opening the Idea of Angular Acceleration

When a rigid body rotates, its angular velocity ω\omega can change with time — just as a car’s linear velocity changes when it accelerates. The quantity that measures how fast ω\omega changes is called angular acceleration. It is the rotational analogue of linear acceleration.

For a particle moving along a circle of radius rr, the linear velocity vv and angular velocity ω\omega are related by v=rωv = r\omega. If ω\omega changes, vv changes too, and the linear acceleration aa has two parts: one due to the change in speed (tangential) and one due to the change in direction (centripetal). Angular acceleration directly governs the tangential part.


Definition of Angular Acceleration

Consider a rigid body rotating about a fixed axis. Let its angular velocity at time tt be ω(t)\omega(t) and at a slightly later time t+Δtt + \Delta t be ω(t+Δt)\omega(t + \Delta t). The average angular acceleration over the interval Δt\Delta t is

αav=ω(t+Δt)−ω(t)Δt=ΔωΔt.\alpha_{\text{av}} = \frac{\omega(t + \Delta t) - \omega(t)}{\Delta t} = \frac{\Delta \omega}{\Delta t}.

The instantaneous angular acceleration is the limit of this ratio as Δt→0\Delta t \to 0:

α=lim⁡Δt→0ΔωΔt=dωdt.\alpha = \lim_{\Delta t \to 0} \frac{\Delta \omega}{\Delta t} = \frac{d\omega}{dt}.

Angular acceleration is a vector quantity. Its direction is along the axis of rotation, given by the right-hand rule: if ω\omega increases, α\alpha points in the same direction as ω\omega; if ω\omega decreases, α\alpha points opposite to ω\omega. For fixed-axis rotation, we often treat it as a signed scalar (positive if ω\omega increases in the chosen sense, negative if it decreases). The SI unit is rad/s2\text{rad/s}^2.

Note

Angular acceleration is defined for the entire rigid body — every particle in the body has the same α\alpha at a given instant, because the body rotates as a whole.


Relation Between Angular Acceleration and Linear Acceleration

For a particle at a perpendicular distance rr from the axis, its linear speed is v=rωv = r\omega. Differentiating with respect to time:

dvdt=rdωdt⇒at=rα.\frac{dv}{dt} = r \frac{d\omega}{dt} \quad \Rightarrow \quad a_t = r \alpha.

Here ata_t is the tangential acceleration — the component of linear acceleration that changes the magnitude of velocity (the speed). It is tangent to the circular path.

But the particle also has a centripetal (radial) acceleration ac=v2r=rω2a_c = \frac{v^2}{r} = r\omega^2, which changes the direction of velocity. The total linear acceleration vector a⃗\vec{a} is the vector sum:

a⃗=a⃗t+a⃗c,\vec{a} = \vec{a}_t + \vec{a}_c,

with magnitudes at=rαa_t = r\alpha and ac=rω2a_c = r\omega^2. Since these two components are perpendicular (tangential and radial), the magnitude of total acceleration is

a=at2+ac2=(rα)2+(rω2)2=rα2+ω4.a = \sqrt{a_t^2 + a_c^2} = \sqrt{(r\alpha)^2 + (r\omega^2)^2} = r\sqrt{\alpha^2 + \omega^4}.

Watch out

Do not confuse at=rαa_t = r\alpha with the total linear acceleration aa. The tangential part is only one component; the centripetal part is always present as long as ω≠0\omega \neq 0, even if α=0\alpha = 0.


Properties of Angular Acceleration (as listed in the textbook)

The textbook presents three key properties that follow from the definition and the relation v=rωv = r\omega. Each is derived below.

›Proof

Property 1: If the angular velocity is constant, angular acceleration is zero.

If ω=constant\omega = \text{constant}, then dωdt=0\frac{d\omega}{dt} = 0, so α=0\alpha = 0. This is the rotational analogue of constant linear velocity implying zero linear acceleration. In uniform circular motion (ω\omega constant), the tangential acceleration is zero, but the centripetal acceleration rω2r\omega^2 is non-zero — the particle still accelerates because its direction changes.

›Proof

Property 2: The direction of angular acceleration is the same as the direction of the change in angular velocity.

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