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NCERT Exemplar · Q16

Q.For a point on a rotating rigid body, the graph of its angular position θ\theta (plotted on the vertical axis) against time tt (plotted on the horizontal axis) is a straight line of constant positive slope: θ\theta increases uniformly with tt, passing steadily through successive instants t1<t2<t3t_1 < t_2 < t_3. Is the body rotating clockwise or anti-clockwise? Give the reason.

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A straight-line θ\theta versus tt graph means θ\theta changes at a constant rate, so the angular velocity ω=dθ/dt\omega=d\theta/dt is constant. Its slope here is positive, so θ\theta is increasing. By the standard convention that increasing angular position is measured anti-clockwise, the body turns anti-clockwise.

Concept

Angular velocity is the slope of the angular-position–time graph: ω=dθdt\omega = \dfrac{d\theta}{dt}.

Reasoning

  1. The graph is a straight line, so dθdt\dfrac{d\theta}{dt} is constant — the rotation is uniform.
  2. The slope is positive, so ω>0\omega > 0; the angular position θ\theta keeps increasing with time. …

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