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Q.Adjacent sides of a parallelogram are given by the vectors 2i - j + 2k and i + 5j - k. Find a unit vector in the direction of its diagonal. Also find the area of parallelogram. OR Vectors a = 3i + j + k, b = i - j + 2k and c = 2i - j - k are given. Find the vector d if d is perpendicular to c and d.a = 10, d.b = 1.

Punjab PsebPSEB Punjab Class 12 Board 2017Subjective· 4mImportance★★★★★
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Note: the printed stem gives the two adjacent side vectors but the specific instruction ("find...") appears to be missing from the source; this matches the standard NCERT-style question asking for the unit vector along the diagonal and the parallelogram's area, so both are found here.

Given adjacent sides a⃗=2ı^−ȷ^+2k^\vec a = 2\hat\imath-\hat\jmath+2\hat k and b⃗=ı^−5ȷ^−k^\vec b=\hat\imath-5\hat\jmath-\hat k.

Unit vector along the diagonal: the diagonal of the parallelogram (from the common vertex) is a⃗+b⃗\vec a+\vec b.

a⃗+b⃗=(2+1)ı^+(−1−5)ȷ^+(2−1)k^=3ı^−6ȷ^+k^\vec a+\vec b = (2+1)\hat\imath+(-1-5)\hat\jmath+(2-1)\hat k = 3\hat\imath-6\hat\jmath+\hat k

∣a⃗+b⃗∣=32+(−6)2+12=9+36+1=46|\vec a+\vec b| = \sqrt{3^2+(-6)^2+1^2}=\sqrt{9+36+1}=\sqrt{46}

Unit vector =3ı^−6ȷ^+k^46= \dfrac{3\hat\imath-6\hat\jmath+\hat k}{\sqrt{46}}

Area of the parallelogram =∣a⃗×b⃗∣=|\vec a\times\vec b|:

a⃗×b⃗=∣ı^ȷ^k^2−121−5−1∣\vec a\times\vec b = \begin{vmatrix}\hat\imath & \hat\jmath & \hat k\\2 & -1 & 2\\1 & -5 & -1\end{vmatrix}

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