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Q.If vector a = 2i - 3j + 4k and vector b = 5i + j - k represent the sides of a parallelogram, then find both diagonals and a unit vector perpendicular to both diagonals.

Punjab PsebPSEB Punjab Class 12 Board 2018Subjective· 4mImportance★★★★★
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The diagonals of a parallelogram with adjacent sides a⃗,b⃗\vec a,\vec b are a⃗+b⃗\vec a+\vec b and b⃗−a⃗\vec b-\vec a; a vector perpendicular to both is their cross product, normalized.

a⃗=2ı^−3ȷ^+4k^\vec a=2\hat\imath-3\hat\jmath+4\hat k, b⃗=5ı^+ȷ^−k^\vec b=5\hat\imath+\hat\jmath-\hat k are the two adjacent sides of the parallelogram.

Diagonals:

d⃗1=a⃗+b⃗=(2+5)ı^+(−3+1)ȷ^+(4−1)k^=7ı^−2ȷ^+3k^\vec d_1=\vec a+\vec b = (2+5)\hat\imath+(-3+1)\hat\jmath+(4-1)\hat k = 7\hat\imath-2\hat\jmath+3\hat k

d⃗2=b⃗−a⃗=(5−2)ı^+(1+3)ȷ^+(−1−4)k^=3ı^+4ȷ^−5k^\vec d_2=\vec b-\vec a = (5-2)\hat\imath+(1+3)\hat\jmath+(-1-4)\hat k = 3\hat\imath+4\hat\jmath-5\hat k

Unit vector perpendicular to both diagonals: their cross product d⃗1×d⃗2\vec d_1\times\vec d_2 is perpendicular to both.

d⃗1×d⃗2=∣ı^ȷ^k^7−2334−5∣\vec d_1\times\vec d_2 = \begin{vmatrix}\hat\imath&\hat\jmath&\hat k\\7&-2&3\\3&4&-5\end{vmatrix}

ı^\hat\imath: (−2)(−5)−(3)(4)=10−12=−2(-2)(-5)-(3)(4) = 10-12=-2

ȷ^\hat\jmath: −[(7)(−5)−(3)(3)]=−[−35−9]=44-[(7)(-5)-(3)(3)] = -[-35-9]=44

k^\hat k: (7)(4)−(−2)(3)=28+6=34(7)(4)-(-2)(3) = 28+6=34

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