Skip to content
Question of 112

Q.Write the hybridization of the central atom and the structure of the following compounds:

(i) PCl5
(ii) SF6
(iii) CH4
Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2018Subjective· 3mImportance★★★★★
0% · 0/112 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

PCl5 is sp3d hybridized with a trigonal bipyramidal shape, SF6 is sp3d2 hybridized with an octahedral shape, and CH4 is sp3 hybridized with a tetrahedral shape.

  1. PCl5: Phosphorus (ground state 3s2 3p3) promotes one 3s electron to an empty 3d orbital, giving 5 unpaired electrons which mix to form 5 equivalent sp3d hybrid orbitals. These 5 hybrid orbitals overlap with 5 chlorine atoms, giving a trigonal bipyramidal structure — 3 chlorine atoms in the equatorial plane (120° apart) and 2 chlorine atoms in axial positions (90° to the equatorial plane, 180° to each other).
  2. SF6: Sulphur (ground state 3s2 3p4) promotes electrons from 3s and 3p into empty 3d orbitals to give 6 unpaired electrons, which mix to form 6 equivalent sp3d2 hybrid orbitals. These overlap with 6 fluorine atoms symmetrically, giving an octahedral structure with all F–S–F bond angles of 90° (and 180° for opposite pairs). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.