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Q.Show that the points (−2,3,5)(-2,3,5), (1,2,3)(1,2,3) and (7,0,−1)(7,0,-1) are collinear.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2023Subjective· 3mImportance★★★★★
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A(−2,3,5)A(-2,3,5), B(1,2,3)B(1,2,3), C(7,0,−1)C(7,0,-1) are collinear because BC⃗\vec{BC} is a scalar multiple of AB⃗\vec{AB}.

Compute the direction ratios of AB⃗\vec{AB} and BC⃗\vec{BC}:

AB⃗=(1−(−2), 2−3, 3−5)=(3,−1,−2)\vec{AB} = (1-(-2),\ 2-3,\ 3-5) = (3,-1,-2)

BC⃗=(7−1, 0−2, −1−3)=(6,−2,−4)\vec{BC} = (7-1,\ 0-2,\ -1-3) = (6,-2,-4)

Notice BC⃗=2(3,−1,−2)=2 AB⃗\vec{BC} = 2(3,-1,-2) = 2\,\vec{AB} — the direction ratios are proportional, meaning AB⃗\vec{AB} and BC⃗\vec{BC} are parallel. Since they also share the common point BB, the three points AA, BB, CC must lie on the same straight line.

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