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Q.Find the length of the medians of the triangle with vertices A(0,0,6)A(0, 0, 6), B(0,4,0)B(0, 4, 0) and C(6,0,0)C(6, 0, 0).

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2026Subjective· 3mImportance★★★★★
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The three medians have lengths 77, 34\sqrt{34}, and 77.

Given A(0,0,6)A(0,0,6), B(0,4,0)B(0,4,0), C(6,0,0)C(6,0,0). A median joins a vertex to the midpoint of the opposite side.

Median from AA (to midpoint of BCBC): midpoint of BC=(0+62,4+02,0+02)=(3,2,0)BC = \left(\dfrac{0+6}{2},\dfrac{4+0}{2},\dfrac{0+0}{2}\right)=(3,2,0).

Length =(3−0)2+(2−0)2+(0−6)2=9+4+36=49=7=\sqrt{(3-0)^2+(2-0)^2+(0-6)^2}=\sqrt{9+4+36}=\sqrt{49}=7

Median from BB (to midpoint of ACAC): midpoint of AC=(3,0,3)AC = (3,0,3).

Length =(3−0)2+(0−4)2+(3−0)2=9+16+9=34=\sqrt{(3-0)^2+(0-4)^2+(3-0)^2}=\sqrt{9+16+9}=\sqrt{34}

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