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Q.Find the equation of the set of points which are equidistant from the points (1,2,3)(1,2,3) and (3,2,−1)(3,2,-1).

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2024Subjective· 3mImportance★★★★★
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The set of points equidistant from (1,2,3)(1,2,3) and (3,2,−1)(3,2,-1) is the plane x−2z=0x-2z=0.

Let P(x,y,z)P(x,y,z) be any point equidistant from A(1,2,3)A(1,2,3) and B(3,2,−1)B(3,2,-1), so PA2=PB2PA^2=PB^2:

(x−1)2+(y−2)2+(z−3)2=(x−3)2+(y−2)2+(z+1)2(x-1)^2+(y-2)^2+(z-3)^2=(x-3)^2+(y-2)^2+(z+1)^2

The (y−2)2(y-2)^2 term is identical on both sides and cancels. Expand the rest:

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