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Q.The path of projectile motion is ________.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2024Subjective· 1mImportance★★★★★
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The trajectory traced by a projectile (launched at an angle to the horizontal, under gravity alone) is a parabola.

For a projectile launched with initial speed u at angle θ, the horizontal motion has constant velocity u cos θ (no horizontal force, ignoring air resistance), so x = (u cos θ) t. The vertical motion is uniformly accelerated by gravity, so y = (u sin θ) t − ½gt^2.

Eliminating t (t = x / (u cos θ)) and substituting into the y-equation gives: …

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