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Q.Draw the resonating structures of phenoxide ion.

Rajasthan RbseRajasthan Board Senior Secondary Examination 2019Subjective· 1mImportance★★★★★
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In the phenoxide ion, the lone pair on the negatively charged oxygen conjugates with the benzene ring pi system, spreading the negative charge onto the ortho and para carbons through resonance.

When phenol loses a proton, the resulting phenoxide ion, C6H5-O-, has a full negative charge on oxygen, which is directly attached to the sp2 carbon of the benzene ring. The lone pair on this oxygen can delocalise into the ring's pi-electron system, giving several resonance (canonical) structures:

  1. Negative charge localised on the oxygen atom (the ring is a normal benzene ring with alternating double bonds) - the main contributor.
  2. Negative charge shifted to the ortho carbon (C2), with a C=O double bond now shown between the ring carbon (C1) and oxygen, and the ring's double bonds rearranged.
  3. Negative charge shifted to the para carbon (C4), similarly with C1=O double bond.
  4. Negative charge on the other ortho carbon (C6) (equivalent to structure 2 by symmetry). …

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