Q.A manufacturer of electronic circuits has a stock of 200 resistors, 120 transistors and 150 capacitors and is required to produce two types of circuits A and B. Type A requires 20 resistors, 10 transistors and 10 capacitors. Type B requires 10 resistors, 20 transistors and 30 capacitors. If the profit on type A circuit is Rs 50 and that on type B circuit is Rs 60, formulate this problem as a LPP so that the manufacturer can maximise his profit.
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Start your 14-day free trial to unlock the full solution →Let and be the numbers of type A and type B circuits. Turning each stock limit into a linear inequality gives the LPP: Maximise subject to , , , .
Why this is a Linear Programming Problem
The stock of resistors, transistors and capacitors is limited, and the two circuits use these parts in fixed amounts while each earns a fixed profit. Deciding how many of each circuit to make so that no stock is exceeded and the profit is greatest is exactly a linear programming problem (LPP): a linear objective to maximise, subject to linear inequality constraints and non-negativity conditions.
Step-by-step formulation
1. Decision variables.
Let = number of type A circuits and = number of type B circuits, with , .
2. Resource constraints.
Type A uses 20 resistors, 10 transistors, 10 capacitors; type B uses 10 resistors, 20 transistors, 30 capacitors. Stock available: 200 resistors, 120 transistors, 150 capacitors.
- Resistors:
- Transistors:
- Capacitors:
Match each resource to the correct product: type A uses 20 resistors, so the coefficient of in the resistor constraint is 20, not 10.
3. Objective function. …
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